Система уравнений x^2+y^2=16,x-y=4

[latex] \left \{ {{ x^{2} +y^2=16} \atop {x-y=4}} \right. [/latex] [latex] \left \{ {{ (x-y)^2+2xy=16} \atop {x-y=4}} \right. [/latex] [latex] \left \{ {{ 4^2+2xy=16} \atop {x-y=4}} \right. [/latex] [latex] \left \{ {{16+2xy=16} \atop {x-y=4}} \right. [/latex] [latex] \left \{ {{2xy=0} \atop {x-y=4}} \right. [/latex] [latex] \left \{ {{xy=0} \atop {x=4+y}} \right. [/latex] [latex] \left \{ {{y(4+y)=0} \atop {x=4+y}} \right. [/latex] [latex]y=0[/latex]   или [latex]y+4=0[/latex]                    [latex]y=-4[/latex] [latex] \left \{ {{y=0} \atop {x=4}} \right. [/latex]   или   [latex] \left \{ {{y=-4} \atop {x=0}} \right. [/latex] Ответ: (0;-4);  (4;0)