Сократите дробь:  6а^2+11a+3 / 3+5a-12a^2

[latex] \frac{6a^2+11a+3}{3+5a-12a^2}; [/latex] [latex]D=121-72=49; x_1=- \frac{1}{3};x_2=- \frac{3}{2};[/latex] [latex]D=25+144=169;x_1= \frac{3}{4};x_2=- \frac{1}{3}.[/latex]  [latex] \frac{6a^2+11a+3}{3+5a-12a^2}= \frac{(3x+1)(2x+3)}{-(4x-3)(3x+1)} =- \frac{2x+3}{4x-3} [/latex]