Срочно!!! решите уравнение: x^5+x^4-x^3-x^2-6x-6=0 

[latex] x^{5} + x^{4} - x^{3} - x^{2} -6x-6=0 \\ x^{4} (x+1)- x^{2} (x+1)-6(x+1)=0 \\ ( x^{4} - x^{2} -6)(x+1)=0 \\ x^{4} - x^{2} -6=0 \\ x^{2} =t \\ t ^{2} -t-6=0 \\ D=25 \\ \sqrt{D} =5 \\ t _{1} = \frac{1+5}{2} = \frac{6}{2} =3 \\ t _{1} = \frac{1-5}{2} = \frac{-4}{2} =-2 \\ x^{2} \neq -2 \\ \\ x^{2} =3\\x=+- \sqrt{3} \\ [/latex] [latex]\\ x+1=0\\x=-1 [/latex]