Срочно,нужна помощь.x/(x+3)+(4x+6)/(x^2+4x+3)=0 (полное решение)

х/(х+3) + (4х+6)/(х^2+4x+3) = 0 x^2 + 4x + 3 = 0 x(1) + x(2) = -4 x(1)*x(2)  = 3 x(1) = -1 x(2) = -3 х/(х+3) + (4х+6)/(х+1)(x+3) = 0 x*(x+1)/(x+3)(x+1) + (4x+6)/(x+1)(x+3) = 0 (x^2+x+4x+6)/(x+1)(x+3) = 0 (x^2+5x+6)/(x+1)(x+3) = 0 x^2+5x+6=0 x(1) + x(2) = -5 x(1)*x(2)  = 6 x(1) = -3 x(2) = -2 (x+2)(x+3)/(x+1)(x+3) = 0 (x+2)/(x+1)=0 x+1≠0 x≠-1 x+2=0  x=-2  Ответ: -2