Упростить: 2sin^2 a-1/sin a + cos a

[latex] \frac{2sin^2 \alpha -1}{sin \alpha +os \alpha } = \frac{2sin^2 \alpha -(sin^2 \alpha +cos^2 \alpha )}{sin \alpha +cos \alpha } =\frac{sin^2 \alpha -cos^2 \alpha }{sin \alpha +cos \alpha }=\\\\=\frac{(sin \alpha -cos \alpha )(sin \alpha +cos \alpha )}{sin \alpha +cos \alpha } =sin \alpha -cos \alpha [/latex]