Вычислите а) arcs in (-1:2) б) cos ( 2 arcs in 1:2) 17pi в)cos ----- 3 г) tg 600
Вычислите а) arcs in (-1:2) б) cos ( 2 arcs in 1:2) 17pi в)cos ----- 3 г) tg 600
Гость
Ответ(ы) на вопрос:
Гостьa)arcsin((-1) / 2) = -0.523598776
arccos(-1) = 3.14159265) б) cos(arcsin(-1/2)-arcsin 1) arcsin(-1/2) = -π/6 arcsin 1 = π/2 cos(arcsin(-1/2)-arcsin 1)= = cos(-π/6-π/2)= = cos(-4π/6) = = cos(2π/3) = = -1/2 в)sin (17 pi/3) cos (5pi/4) = 1/2{2sin(17pi/3) cos(5pi/4)}
= 1/2{2 sin(6pi - pi/3) cos (pi +pi/4)
= 1/2{ -2sin(pi/3) (- cos(pi/4)}
= 1/2{2sin(pi/3) cos(pi/4)}
= 1/2{ sin(pi/3+pi4) + sin(pi/3- pi/4)}
= 1/2{ sin(7pi/12) +sin(pi/12}}
= 1/2{ sin (105) + sin (15)}
= 1/2{sin(90+15) + sin(15)}
= 1/2{ cos(15) +sin(15)}
= 1/2{cos(45-30) + sin(45-30)}
=1/2[{cos(45)cos (30)+sin(45)sin(30)} + {sin(45)cos(30) - cos(45) sin(30)}]
=1/2{2 (1/sqrt(2))(sqrt(3)/2 )
= 1/2{sqrt(3/2)} г)
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