Вычислите интегралы! Как надо оформлять, смотрите фото номер 2!!

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[latex]1)\; \; f(x)=x^{-2}+x^2\\\\F(x)=-\frac{1}{x}+\frac{x^3}{3}\\\\F(2)=-\frac{1}{2}+\frac{8}{3}= \frac{-3+16}{6} =\frac{13}{6}\\\\F(1)=-1+\frac{1}{3}=-\frac{2}{3}\\\\\int _{1}^2(x^{-2}+x^2)dx=F(2)-F(1)=\frac{13}{6}+\frac{2}{3}=\frac{17}{6} [/latex] [latex]2)\; \; f(x)=cos2x\\\\F(x)=\frac{1}{2}sin2x\\\\F(\frac{\pi}{6})=\frac{1}{2}sin\frac{\pi}{3}=\frac{1}{2}\cdot \frac{\sqrt3}{2}=\frac{\sqrt3}{4}\\\\F(\frac{\pi}{12})=\frac{1}{2}sin\frac{\pi}{6}=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}\\\\\int _{\frac{\pi}{12}}^{\frac{\pi}{6}}\, cos\, 2x\, dx=F(\frac{\pi}{6})-F(\frac{\pi}{12})=\frac{\sqrt3}{4}-\frac{1}{4}=\frac{\sqrt3-1}{4}[/latex]