Вычислите: п.с 91(в третьей)+28(в третьей)/ 119 записано дробью

[latex](65^{2}-16^{2})/ ( \frac{(91^{2}+28^{2})}{119} - 91*28 ) =[/latex] 1   [latex]\frac{(91^{2}+28^{2})}{119} - 91*28 ) = \frac{(91+28)(91^{2}-91*28+28^{2})}{119} - 91*28 ) = [/latex][latex] \frac{119(91^{2}-91*28+28^{2})}{119} - 91*28 ) = (91^{2}-91*28+28^{2}) - 91*28 ) =  [/latex][latex]91^{2}-2*91*28+28^{2} = (91-28)^{2} = 63^{2}[/latex]   [latex]\frac{65^{2}-16^{2}}{63^{2}} = \frac{(65-16)(65+16)}{63^{2}} = \frac{49*81}{63^{2}}=\frac{3969}{3969} = 1[/latex]