Вычислите значение предела lim(x-0) (3x^2 + x) / (x^2 - 2x)

[latex] \lim_{x \to0} \frac{3 x^{2}+x}{ x^{2} -2x} = \frac{3*0 ^{2} +0}{ 0^{2} -2*0} =[ \frac{0}{0} ][/latex] [latex] \lim_{x \to 0} \frac{3 x^{2} +x}{ x^{2} -2x}= \lim_{x \to 0} \frac{x*(3x+1)}{x*(x-2)} = \lim_{x \to 0} \frac{3x+1}{x-2} = \frac{3*0+1}{0-2} =- \frac{1}{2} =-0,5[/latex]