( x + 3 )^4 - 3(x + 3 )^2 - 4 = 0

х+3=а а∧4-3а∧2-4=0 а∧2=б б∧2-3б-4=0 д=9-4*1*(-4)=25 б1=(3-5)/2=-1 б2=(3+5)/2=4 а∧2=-1 корней нет а∧2=4 а1=2 а2=-2 х+3=2 х=2-3 х1=-1 х+3=-2 х2=-5

( х + 3 )^4 - 3( х + 3 )^2 - 4 = 0 ( х + 3 )^2 = а ; а > 0 а^2 - 3а - 4 = 0 D = 9 + 16 = 25 ; V D = 5 a1 = ( 3 + 5 ) : 2 = 4 a2 = ( 3 - 5 ) : 2 = - 1 ( < 0 ) ( x + 3 )^2 = 4 x^2 + 6x + 9 - 4 = 0 x^2 + 6x + 5 = 0 D = 36 - 20 = 16 ; V D = 4 x1 = ( - 6 + 4 ) : 2 = - 1 x2 = ( - 6 - 4 ) : 2 = - 5 Ответ : ( - 1 ) ; ( - 5 )