X²+y=3 y-x+3=0 решите систему

Х^2 + y = 3 y - x + 3 = 0 •••••••••••••• y = 3 - x^2 y = x - 3 •••••••••••••• 3 - x^2 = x - 3 X^2 - 3 + x - 3 = 0 X^2 + x - 6 = 0 D = 1 + 24 = 25 = 5^2 X1 = ( - 1 + 5 ) : 2 = 2 X2 = ( - 1 - 5 ) : 2 = - 3 y = x - 3 y1 = 2 - 3 = - 1 y2 = - 3 - 3 = - 6 Ответ ( 2 ; - 1 ) ; ( - 3 ; - 6 )