X+1/1-x=2x+3 помогите срочно

x+1=(2x+3)(1-x)..... x+1=2x-2x^2+3-3x.... x+1=-2x^2-x+3.... -2x^2-2x+2=0 2x^2+2x-2=0 x^2+x-1=0 d=1-4*(-1)=1+4=√5 x1=(-1+√5)/2 x2=(-1-√5)/2 ========================= [latex]x+1=(2x+3)*(1-x) \\ x+1=2x-2 x^{2} +3-3x \\ x+1=-2 x^{2} -x+3 \\ -2 x^{2} -2x+2=0 \\ 2 x^{2} +2x-2=0 \\ x^{2} +x-1=0 \\ \sqrt{D} = 1^{2} -4*1*(-1)= \sqrt{5} \\ x_{1} = \frac{-1+ \sqrt{5} }{2} \\ x_{2} = \frac{-1- \sqrt{5} }{2} [/latex]