|x^2-4x|=5|x^2-1|+x=5_________^2 - квадратный корень.Помогите с решением пожалуйста

[latex]|x^2-4x|=5, \\ \left \ [ {{x^2-4x=5,} \atop {x^2-4x=-5;}} \right. \ \ \ \left \ [ {{x^2-4x-5=0,} \atop {x^2-4x+5=0;}} \right. \ \ \ \left \ [ {{ \left \ [ {{x=-1,} \atop {x=5,}} \right. } \atop {x\in\varnothing; (D=-4<0)}} \right. \ \ \ \left \ [ {{x=-1,} \atop {x=5.}} \right.[/latex] [latex]|x^2-1|+x=5, \ |x^2-1|=5-x, \\ 5-x\geq0, -x\geq-5, x\leq5;\\ \left \ [ {{x^2-1=5-x,} \atop {x^2-1=x-5;}} \right. \ \ \ \left \ [ {{x^2+x-6=0,} \atop {x^2-x+4=0;}} \right. \ \ \ \left \ [ {{ \left \ [ {{x=-3,} \atop {x=2,}} \right. } \atop {x\in\varnothing; \ (D=-15<0)}} \right. \ \ \ \left \ [ {{x=-3,} \atop {x=2.}} \right. [/latex]