X(x+2)(x+3)(x+5)=72 помогите пож

x(x+5)(x+2)(x+3) = 72 (x² + 5x)(x² + 5x + 6) = 72 x² + 5x = t t(t+6) = 72 t²+ 6t - 72 = 0 D = 36 + 288 = 324 = 18² t1 = (-6-18)/2 = -12 t2 = (-6+18)/2 = 6 x² + 5x = -12 x² + 5x + 12 = 0 D = 25 - 48 < 0 x² + 5x = 6 x² + 5x - 6 = 0 D = 25 + 24 = 49 = 7² x1 = (-5-7)/2 = -6 x2 = (-5+7)/2 = 1 Ответ: -6 и 1