Y²-4=0 121-x²=0 1.96-y²=0 решите прошу

y=+2;-2 x=11;-11 y=1,4;-1,4

[latex]y^2 - 4 = 0 (y - 2)(y + 2) = 0 y1 = 2 ; y2 = -2[/latex] [latex]121 - x^2 = 0 (x - 11)(x + 11) = 0 x1 = 11 ; x2 = -11[/latex] [latex]1,96 - y^2 = 0 [/latex] [latex] \frac{49}{25} - y^2 = 0[/latex] [latex]- \frac{1}{25} (5y - 7)(5y + 7) = 0 (5y - 7)(5y + 7) = 0 [/latex] [latex]y1 = \frac{7}{5} [/latex] [latex]y2 = -\frac{7}{5} y1 = 1,4 ; y2 = -1,4[/latex]