Y=36tgx-36x+9π-4 найдите наиб значение функции на отрезке [-π/4;π/4]    

y=36tgx-36x+9π-4 1) ооф: x - любое число 2) y' = 36 / cos^2(x) - 36 = (36 - 36cos^2(x)) / cos^2(x) 3) y' = 0 => 36 - 36cos^2(x) = 0 -cos^2(x)=-1 cosx = 1 => x = 2πn - не принадлежит [-π/4;π/4] cosx = -1 => x = π + 2πn - не принадлежит [-π/4;π/4] 4) y(-π/4) = 36tg(-π/4) - 36(-π/4) + 9π - 4 = -36 + 9π + 9π + 4 = -32 + 18π y(π/4) = 36tg(π/4) - 36(π/4) + 9π - 4 = 36 - 9π + 9π + 4 = 40   Ответ: 40.