{y=x-1 {5x+2y=16 Тема: решение систем линейных уравнений способом подстановки

[latex] \left \{ {{y=x-1} \atop {5x+2y=16}} \right. [/latex] [latex] \left \{ {{y=x-1} \atop {5x+2(x-1)=16}} \right. [/latex] [latex] \left \{ {{y=x-1} \atop {5x+2x-2=16}} \right. [/latex] [latex] \left \{ {{y=x-1} \atop {7x=18}} \right. [/latex] [latex] \left \{ {{y=x-1} \atop {x=2 \frac{4}{7} }} \right. [/latex] [latex] \left \{ {{y=2 \frac{4}{7} -1} \atop {x=2 \frac{4}{7} }} \right. [/latex] [latex] \left \{ {{y=1 \frac{4}{7}} \atop {x=2 \frac{4}{7} }} \right. [/latex] Ответ: [latex](2 \frac{4}{7}; 1 \frac{4}{7})[/latex]