Контрольная работа: Оценка напряженно-деформированного состояния массива пород

U₁₀ = 5.8*1.2/ 3.2*10⁴ *1.9 = 0.000413

U₁₁ = 5.8*1.2/ 3.2*10⁴ *2.0 = 0.000435

6. Определяем радиальные и тангенциальные деформации εθ, εr

εθ =(1/E)*(σθ-0.2*σr)

εr=(1/E)*(σr -0.2*σθ)

1) εθ =(1/E)*(σθ-0.2*σr)

εθ1 = (1/3.2*10⁴ )*(11.6-0,2*0.000)= 0.000362

εθ2 = (1/3.2*10⁴ )*(10.593-0,2*1.006)= 0.000324

εθ3 = (1/3.2*10⁴ )*(9.827-0,2*1.772)= 0.000296

εθ4 = (1/3.2*10⁴ )*(9.231-0,2*2.368)= 0.000273

εθ5 = (1/3.2*10⁴ )*(8.759-0,2*2.840)= 0.000255

εθ6 = (1/3.2*10⁴ )*(8.377-0,2*3.222)= 0.000241

εθ7 = (1/3.2*10⁴ )*(8.065-0,2*3.534)= 0.000229

εθ8 = (1/3.2*10⁴ )*(7.806-0,2*3.793)= 0.000220

εθ9 = (1/3.2*10⁴ )*(7.590-0,2*4.009)= 0.000212

εθ10 = (1/3.2*10⁴ )*(7.406-0,2*4.193)= 0.000205

εθ11 = (1/3.2*10⁴ )*(7.25-0,2*4.35)= 0.000199

2) εr=(1/E)*(σr -0.2*σθ)

εr₁ = (1/3.2*10⁴ )*(0.000-0,2*11.6)= -0.000072

εr₂ = (1/3.2*10⁴ )*(1.006-0,2*10.593)= -0.000034

εr₃ = (1/3.2*10⁴ )*(1.772-0,2*9.827)= -0.000006

εr₄ = (1/3.2*10⁴ )*(2.368-0,2*9.231)= 0.000016

εr₅ = (1/3.2*10⁴ )*(2.840-0,2*8.759)= 0.000034

εr₆ = (1/3.2*10⁴ )*(3.222-0,2*8.377)= 0.000048

εr₇ = (1/3.2*10⁴ )*(3.534-0,2*8.065)= 0.000060

εr₈ = (1/3.2*10⁴ )*(3.793-0,2*7.806)= 0.000069

εr₉ = (1/3.2*10⁴ )*(4.009-0,2*7.590)= 0.000077

εr₁₀ = (1/3.2*10⁴ )*(4.193-0,2*7.406)= 0.000084

εr₁₁ = (1/3.2*10⁴ )*(4.35-0,2*7.25)= 0.000090