Реферат: Решение дифференциальных уравнений 1 порядка методом Эйлера

{

double h,Xi,Yi,Xkon,kx,ky;

int n;

cout<<"\t"<<"\t"<<"************************************************n";

cout<<"\t"<<"\t"<<"* * "<<"\n";

cout<<"\t"<<"\t"<<"* Reshenie difurov 1 poryadka methodom Eulera *"<<"\n";

cout<<"\t"<<"\t"<<"*************************************************

cout<<endl;

cout<<"Vvedite nachaloe znachenie intervala [a,b]=";

cin>>Xi;

cout<<"Vvedite konechoe znachenie intervala [a,b]=";

cin>>Xkon;

cout<<"Vvedite chislo shagov=";

cin>>n;

h=(Xkon- Xi)/n;

cout<<endl;

cout<<"Vvedite nachalnoe uslovie y=";

cin>>Yi;

cout<<"Vvedite koefitsient pri x=";

cin>>kx;

cout<<"Vvedite koefitsient pri y=";

cin>>ky;

cout<<"|Interval|Chislo shagov|Shag prirasheniya|Nacalnoe Y|Uravnenie vida:| "<<"\n";

cout<<"|--------|-------------|-----------------|----------|---------------|"<<"\n";

cout<<"|"<<"["<<Xi<<","<<Xkon<<"]" <<" |"<<n<<" |"<<h<<" |"<<Yi<<" |"<<"y'="<<kx<<"x"<<"+"<<ky<<"y"<<" |"<<"\n";

cout<<endl;

cout<<endl;

for (int i=1;i<=n;i++)

{