2n
2
)
x2n–2 +
(
4
x2n–4 + ... +
2n–2
x2 + 1;
f (x) = 1 –
x2
2!
+
x4
4!
–
x6
6!
x8
8!
.
Решение
p1 = x·x = x2, p2 = x2·x2 = x4,