1) (1,6*10^-5)(4*10^2) 2)18-х^2=14 3) х^2+2=х+2 4) х(х+3)=4 5)х(х-4)=-3
1) (1,6*10^-5)(4*10^2)
2)18-х^2=14
3) х^2+2=х+2
4) х(х+3)=4
5)х(х-4)=-3
Гость
Ответ(ы) на вопрос:
Гость1) (1,6*10⁻⁵)(4*10²) = 6,4*10²⁻⁵ = 6,4*10⁻³
2) 18 - х² = 14
18 - 14 = х²
х² = 4
х = 2; х = -2
3) x² + 2 = x + 2
x² - x = 0
x(x - 1) = 0
x = 0; x = 1
4) x(x + 3) = 4
x² + 3x - 4 = 0 D = b²-4ac = 9+16 = 25
x₁ = (-b+√D)/2a = (-3+5)/2 = 1
x₂ = (-b-√D)/2a = (-3-5)/2 = -4
5) x(x - 4) = -3
x² - 4x + 3 = 0 D = b²-4ac = 16-12 = 4
x₁ = (-b+√D)/2a = (4+2)/2 = 3
x₂ = (-b-√D)/2a = (4-2)/2 = 1
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