1) (2x+10) (x-1)+5(x-2)=2(7+x)2) 1+3(2x-4)+(2x-1)(3-2x)=8

[latex](2x+10) (x-1)+5(x-2)=2(7+x)[/latex] [latex]2 x^2-2 x+10 x-10+5 x-10-14-2 x=0[/latex] [latex]2 x^2+11 x-34 = 0[/latex] [latex]D = b^2-4ac = 393[/latex] [latex]x_{1,2}= \frac{-b\pm\sqrt{D}}{2a} = \frac{-11\pm\sqrt{393}}{4} = \frac{-11\pm\sqrt{393}}{4}[/latex] Ответе: [latex]x_1 = \frac{-11+\sqrt{393}}{4},\; x_2 = \frac{-11-\sqrt{393}}{4}[/latex] 2) [latex]1+3(2x-4)+(2x-1)(3-2x)=8[/latex] [latex]-7+6 x-12+6 x-4 x^2-3+2 x=0[/latex] [latex]-4 x^2+14 x-22 =0[/latex] [latex]D = b^2-4ac = -156[/latex] Ответ: корней нет, т.к. D<0