1) sin5α·cos2α=2) cos6α·cos(-15α)=3) sin3α·sin(-21α)=4) sin[latex] \pi [/latex]+5α)·cos(3[latex] \pi [/latex]-3α)=5) cos7α·cos(2[latex] \pi [/latex]+9α)=1) 2sinαcos3α=2) 2cos2αcosα=

Question

1) sin5α·cos2α=2) cos6α·cos(-15α)=3) sin3α·sin(-21α)=4) sin[latex] \pi [/latex]+5α)·cos(3[latex] \pi [/latex]-3α)=5) cos7α·cos(2[latex] \pi [/latex]+9α)=1) 2sinαcos3α=2) 2cos2αcosα=

1) sin5α·cos2α= 2) cos6α·cos(-15α)= 3) sin3α·sin(-21α)= 4) sin[latex] \pi [/latex]+5α)·cos(3[latex] \pi [/latex]-3α)= 5) cos7α·cos(2[latex] \pi [/latex]+9α)= 1) 2sinαcos3α= 2) 2cos2αcosα=

Гость

Ответ(ы) на вопрос:

Accepted Answer

Гость

X^4+X^2-20 или же X^4-6X-27