1) сократите дробь: [latex] \frac{(ab+ac)^{2} }{ab^{2}-ac^{2} } [/latex] 2) упростите выражение: [latex]( \frac{1}{c} - \frac{1}{10-c} )*( \frac{25}{c-5} -c+5)[/latex] СРОЧНО НАДО

1 (ab+ac)²/(ab²-ac²)=a²(b+c)/a(b²-c²)=a(b+c)/(b-c)(b+c)=a/(b-c) 2 1)1/c-1/(10-c)=(10-c-c)/c(10-c)=(10-2c)/c(10-c)=2(5-c)/c(10-c)=2(c-5)/c(c-10) 2)25/(c-5) -(c-5)=(25-c²+10c-25)/(c-5)=(10c-c²)/(c-5)=c(10-c)/(c-5) 3)2(c-5)/c(c-10) * c(10-c)/(c-5)=-2