1) (x²+2x)² -11(x+1)² +35=0 2) (x²+2x)² -11(x-1)² +35=0

[latex]1. \ \ (x^2+2x)^2 -11(x+1)^2 +35=0 \\ ((x+1)^2 -1)^2-11(x+1)^2 +35=0 |\ t=(x+1)^2 \\ (t-1)^2 - 11t + 35 = 0 \\ t^2 - 13t + 36 = 0 \Rightarrow t_{1,2} = 4,9 \\ \\ (x+1)^2 = 4 \Rightarrow x_{1,2} = 1,-3 \\ (x+1)^2 = 9 \Rightarrow x_{3,4} = 2,-4.[/latex] Второе решается аналогично.