10х=4,6+3у 4у+3,2=6х решить систему уравнений

[latex] \left \{ {{10x=4.6+3y} \atop {4y+3.2=6x}} \right. \left \{ {{10x-3y=4.6} \atop {-6x+4y=-3.2}} \right. \left \{ {{40x-12y=18.4} \atop {-18x+12y=-9.6}} \right. 22x=8.8 x=0.4 16x-12y=18.4 -12y=2.4 y=-0.2[/latex]