1/9х2 х 3^4(степень)-2/81 х 3^5(степень)=? Решил по действиям, но с ответом не сошлось, помогите

[latex]\frac{1}{9}*2*3^4- \frac{2}{81}*3^5= (\frac{1}{9}*2)*3^4- \frac{2}{81}*3^5= \\\\ = \frac{2}{9}*3^4- \frac{2}{81}*3^5= \frac{2}{9}*3^4- \frac{2}{81}*3^4*3=\\\\ = \frac{2}{9}*3^4- (\frac{2}{81}*3)*3^4=\frac{2}{9}*3^4- \frac{2}{27}*3^4=\\\\ 3^4*( \frac{2}{9}- \frac{2}{27} )=3^4*( \frac{6}{27}- \frac{2}{27} )=3^4* \frac{4}{27}=\\\\ = 81*\frac{4}{27}= \frac{81}{1}*\frac{4}{27}= \frac{3}{1} * \frac{4}{1} = \frac{12}{1} =12[/latex]

[latex] \frac{1}{9} *2*3^4- \frac{2}{81} *3^5= \frac{2*3^4}{3^2} - \frac{2*3^5}{3^4} =2*3^2-2*3=18-6=12[/latex]