1//(a+1)+(2a-10)//(a^2-a-2)+a//(a-2)

[latex]\frac{1}{a+1}+\frac{2a-10}{a^2-a-2}+\frac{a}{a-2}=\frac{1}{a+1}+\frac{2a-10}{(a+1)(a-2)}+\frac{a}{a-2}=\frac{a-2+2a-10+a(a+1)}{(a+1)(a-2)}[/latex] [latex]=\frac{3a-12+a^2+a}{(a+1)(a-2)}=\frac{a^2+4a-12}{(a+1)(a-2)}=\frac{(a+6)(a-2)}{(a+1)(a-2)}=\frac{a+6}{a+1}[/latex]