288÷(144-(×-16)4÷7+108=111

288/(144-x+16)4/7+108=111 288/(160*4+4х)/7+108=111 288/(640-4х)/7+108=111 [latex] \frac{\frac{288}{640-4x}}{7} + 108 = \frac{\frac{288}{4(160-x)}}{7} + 108 = \frac{\frac{72}{160-x}}{7} + 108 - 111 = \frac{\frac{72}{160-x}}{7} -3 = [/latex][latex] \frac{3(160-x)}{\frac{3*7}{7}} = \frac{\frac{72}{160-x}}{7} - \frac{3(160-x)}{\frac{21}{7}} = \frac{72}{160-x} - \frac{3(160 - x)}{21} = [/latex][latex] \frac{72*21}{(160-x)*21} - \frac{3(160 - x) ^{2} }{21(160 - x)} = \frac{1512}{(160-x)*21} - \frac{3(25600 - 2x + x^{2} ) [latex]\frac{1512}{(160-x)*21} - \frac{76800 - 6x + 3x^{2} }{21(160-x)} = \frac{1512-76800 - 6x+3 x^{2} }{21(160-x)} = \frac{ 3x^{2} - 6x - 75288 }{21(160 - x)} =[/latex][latex]\frac{ 3(x^{2} - 2x - 25096) }{21(160 - x)} = \frac{ (x^{2} - 2x - 25096) } {7(160 - x)} = \frac{ (x^{2} - 2x - 25096) }{147 - 7x}[/latex] }{21(160-x)} = [/latex] область определения найди и реши кавдратное уравнение

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