2sinx=√3cos(x+π/3)=-1

2sinx=√3 sinx=√3/2 x=(-1)^n  π/3+πn n∈Z cos(x+π/3)=-1 x+π/3 = π + 2πn n ∈ Z x=2π/3 + 2πn  n∈Z

Ответ: 1)2sinx=_/3 sinx=_/3/2 x=(-1)^k*arcsin(_/3/2)+pik x=(-1)^k*pi/3+pik 2)cos(x+pi/3)=-1 x+pi/3=+-accos(-1)+2pik x+pi/3=+-(pi-arccos1)+2pik    x=+-((pi-2pi)-pi/3)+2pik x=+-(-pi-pi/3)+2pik x=+-(-4pi/3)+2pik