2x-1/2x+1=2x+1/2x-1+8/1-4x^2

[latex]\frac{2x-1}{2x+1}=\frac{2x+1}{2x-1}+\frac{8}{1-4x^2}[/latex] [latex]2x-1 \neq 0; 2x+1 \neq 0; 1-4x^2 \neq 0;[/latex] [latex]x \neq \frac{1}{2}; x \neq -\frac{1}{2}[/latex] [latex](2x-1)^2=(2x+1)^2+8;[/latex] [latex]4x^2-4x+1=4x^2+4x+1+8[/latex] [latex]-8x=8[/latex] [latex]x=8:(-8)[/latex] [latex]x=-1[/latex] отвте: -1