( 2x²-9)(x²+2)-(x²-3)(x²+3)=5x²-18

x1 = 1 x2 = 3 x3 = -3 x4 = -1

(2х^2-9)(х^2+2)-(х^2-3)(х^2+3) = 5х^2-18 2х^4+4х^2-9х^2-18-(х^4-9) = 5х^2-18 2х^4 - 5х^2 - 18 - х^4 + 9 = 5х^2 - 18 х^4 - 5х^2 - 9 = 5х^2 - 18 х^4 - 5х^2 - 9 - 5х^2 + 18 = 0 х^4 - 10х^2 + 9 = 0 х^4 - х^2 - 9х^2 + 9 = 0 х^2(х^2-1)-9(х^2 + 1) = 0 (х^2-9)(х^4-1) = 0 х^2 - 9 = 0 или х^4 - 1 = 0 х = 3 или х = 1 х = -3 или х = -1 Ответ: 3;1;-3;-1