3-cos^x-3sinx=0 pomogite plls zaranee sps

[latex]3-cos^2x-3sinx=0 \\ 3-(1-sin^2x)-3sinx=0 \\ 3-1+sin^2x-3sinx=0 \\ 2+sin^2x-3sinx=0 \\ sinx=t, t^2-3t+2=0 \\ D=B^2-4ac=9-4*1*2=9-8=1 \\ t_1= \frac{-b+D}{2a} = \frac{4}{2} =2 \\ t_2= \frac{-b-D}{2a} = \frac{2}{2} =1 \\sinx=2 \ net \ resheniya \\ sinx=1 \\ x= \frac{ \pi }{2} +2 \pi n[/latex]