3× в кводрате -14 Х + 16= 0

[latex]3x^2-14x+16=0, \\ D_{/4}=(-7)^2-3\cdot16=49-48=1, \\ x=\frac{7\pm1}{3}, \\ x_1=2, \ x_2=2\frac{2}{3}.[/latex]