3 заданиееееееееееееее

а)[latex](4 \sqrt{0.02}+ \sqrt{8})* \sqrt{2}=( \sqrt{16*0.02} + \sqrt{8})* \sqrt{2}=( \sqrt{0.32} + \sqrt{8})* \sqrt{2}= [/latex][latex] \sqrt{2*0.32}+ \sqrt{2*8}= \sqrt{0.64}+ \sqrt{16}=0.8+4=4.8 [/latex][latex]3*2 \sqrt{3}-2*3 \sqrt{2}=6 \sqrt{2}-4 \sqrt{3}+6 \sqrt{3}-6 \sqrt{2}=2 \sqrt{3} [/latex] б)[latex](2+ \sqrt{6})(3 \sqrt{2}-2 \sqrt{3} )=6 \sqrt{2}-4 \sqrt{3}+3 \sqrt{12}-2 \sqrt{18}=6 \sqrt{2}-4 \sqrt{3}+ [/latex] в)[latex]( \sqrt{7}+ \sqrt{3} )( \sqrt{7} - \sqrt{3} )=( \sqrt{7})^2-( \sqrt{3})^2-7-3=4 [/latex]