3*4^×+2*9^×=5*6^×помогите пожалуйста

Решение 3*4^×+2*9^×=5*6^×  3*(2^2x) +2*(3^2x) - 5*(2^x)*(3^x) = 0 делим на (2^x)*(3^x) 3*(2/3)^x  + 2*(1/(2/3)^x) - 5 = 0 (2/3)^x = t 3t + 2/t - 5 = 0 3t² - 5t + 2 = 0 D = 25 - 4*3*2 = 1 t₁ = (5 - 1)/6 t₁ = 2/3 t₂ = (5 + 1)/6 t₂ = 1 1) (2/3)^x = 2/3 x₁ = 1 2)  (2/3)^x = 1 (2/3)^x = (2/3)⁰ x₂ = 0