(3/4)^х-3 ≤ (4/3)^2x+5 решить неравенство у меня экзамен, помогите

[latex](\frac{3}{4})^{x-3}\leq(\frac{4}{3})^{2x+5}\\((\frac{4}{3})^{-1})^{x-3}\leq(\frac{4}{3})^{2x+5}\ \textless \ =\ \textgreater \ (\frac{4}{3})^{3-x}\leq(\frac{4}{3})^{2x+5}\\3-x\leq2x+5\\-2\leq3x\\-\frac{2}{3}\leq x\ \textless \ =\ \textgreater \ x \geq-\frac{2}{3}[/latex] \\\\\\\\\\α\\\\\\β///////////// –––––––––|––––––––> где [latex]a=-\frac{2}{3}[/latex], [latex]\beta=0[/latex]; x∈[[latex]-\frac{2}{3}[/latex]; +∞)