3x^2=2x+4 решить уравнение

3x²=2x+4 3x²-2x-4=0 D=(-2)²-4*(-4)*3=4+48=52 [latex]x_{1}= \frac{-(-2)- \sqrt{52} }{3*2} = \frac{2-2 \sqrt{13} }{6} = \frac{2(1- \sqrt{13}) }{6} = \frac{1- \sqrt{13} }{3} \\ x_{2}= \frac{-(-2)+ \sqrt{52} }{3*2} = \frac{2+2 \sqrt{13} }{6} = \frac{2(1+ \sqrt{13}) }{6} = \frac{1+ \sqrt{13} }{3} \\ [/latex]