Ответ(ы) на вопрос:
9у^2-3+18y+2y+6y=6y 9y^2+20y-3=0
[latex] \frac{3y-3}{3y-2}+ \frac{6+2y}{3y+2}=2 [/latex]
[latex] \frac{(3y+2)*(3y-3)+(3y-2)*(6+2y)}{(3y-2)*(3y+2)}=2 [/latex]
[latex] \frac{9y ^{2}-9y+6y-6+18y+6y ^{2}-12-4y }{9y ^{2}-4 }=2 [/latex]
[latex] \frac{15y ^{2}+11y-18 }{9y ^{2}-4 }=2 [/latex]
[latex]15y ^{2}+11y-18=2*(9y ^{2}-4) [/latex]
[latex]15y ^{2}+11y-18=18y ^{2}-8 [/latex]
[latex]15y ^{2}+11y-18-18y ^{2}+8=0 [/latex]
[latex]-3y ^{2}+11y-10=0 [/latex]
[latex]D=b ^{2}-4ac=11 ^{2}-4*(-3)*(-10)=121-120=1 [/latex]
[latex]y _{1}= \frac{-b+ \sqrt{D} }{2a}= \frac{-11+1}{2*(-3)}= \frac{-10}{-6}= \frac{5}{3}=1 \frac{2}{3} [/latex][latex]y _{2}= \frac{-b- \sqrt{D} }{2a}= \frac{-11-1}{-6}= \frac{-12}{-6}=2 [/latex]
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