(4cos^2x-3)/(log_5(-tgx)=0 CPO4HO

[latex]\frac{4cos^2x-3}{log_5(-tgx)}=0[/latex] [latex]\left \{ {{log_5(-tgx)\neq0} \atop {4cos^2x-3=0}} \right.[/latex]  [latex]\begin{cases} -tgx>0\\-tgx\neq1\\cos^2x=\frac{3}{4} \end{cases}[/latex]  [latex]\begin{cases} x\neq-\frac{\pi}{4}\\x = \frac{\pi}{6}+2\pi k\end{cases}[/latex] [latex]x = \frac{\pi}{6}+2\pi k,[/latex] k целое