4/х = 7/х-3 - х+4/х-3 Пожалуйста, помогите!!!

[latex] \frac{4}{x} [/latex]=[latex] \frac{7}{x-3} [/latex]- [latex] \frac{x+4}{x-3} [/latex] [latex] \frac{4}{x} [/latex]-[latex] \frac{7}{x-3} [/latex]+[latex] \frac{x+4}{x-3} [/latex]=0 [latex] \frac{4(x-3)-7x+x^2+4x}{x(x-3)} [/latex]=0 [latex] \frac{4x-12-7x+x^2+4x}{x(x-3)} [/latex] x≠0; x-3≠0; x≠3 4x-12-7x+x^2+4x=0 x^2+x-12=0 D=1-4*1*(-12)=49 [latex] x_{1} = \frac{-1+7}{2} = 3[/latex] [latex] x_{2} = \frac{-1-7}{2} = -4[/latex]