5\12(с-3)-1\6(2с-7)=2 помогите решить уровнение

5/12(с-3)-1/6(2с-7)=2 5/12с-5/4-1//3с+7/6=2 5/12с-1/3с=2+5/4-7/6 с/12=25/12 с=25

[latex] \frac{5}{12} [/latex](с-3)-[latex] \frac{1}{6} [/latex](2с-7)=2 [latex] \frac{5}{12} [/latex]с-1[latex] \frac{1}{4} [/latex]-[latex] \frac{1}{3} [/latex]с+1[latex] \frac{1}{6} [/latex]=2 [latex] \frac{5}{12} [/latex]с-[latex] \frac{15}{12} [/latex]-[latex] \frac{4}{12} [/latex]с+[latex] \frac{14}{12} [/latex]=2 [latex] \frac{1}{12} [/latex]с-[latex] \frac{1}{12} [/latex]=2 [latex] \frac{1}{12} [/latex]с=2[latex] \frac{1}{12} [/latex] с=[latex] \frac{25}{12} [/latex]*[latex] \frac{12}{1} [/latex] с=25