5/3×(3,7- 1 4/5) решить помогите

[latex] \frac{5}{3} (3,7-1 \frac{4}{5} )= \frac{5}{3} (3 \frac{7}{10} -1 \frac{4}{5} )=\frac{5}{3} ( \frac{37}{10} - \frac{9}{5} )=\frac{5}{3} (\frac{37-2*9}{10} )=\frac{5}{3} *\frac{37-18}{10} =[/latex] [latex]=\frac{5}{3} *\frac{19}{10} =\frac{1}{3} *\frac{19}{2}= \frac{19}{6} = 3 \frac{1}{6}[/latex]