5cosx+2sinx=3 решите пожалуйста

5cosx/2-5sinx/2+4sinx/2cosx/2-3sinx/2-3cosx/2=0/cosx/2 8tgx/2-4tgx/2-2=0 tgx/2=a 8a-4a-2=0 D=16+64=80 a1=(4-4√5)/16=(1-√5)/4tgx/2=(1-√5)/4 x/2=arctg(1-√5)/4+nx=2arctg(1-√5)/4+2n,nz a2=(1+√5)/4tgx/2=(1+√5)/4x/2=arctg(1+√5)/4+k x=2arctg(1+√5)/4+2k,kz