5sin^2t меньше =11sint+12 Решите срочно!!!

[latex]5sin^2t \leq 11sint+12\\\\sint=p,\; \; -1 \leq sint \leq 1\; ,\; \; -1 \leq p \leq 1\\\\5p^2-11p-12 \leq 0\; ,\\\\p_{1,2}=\frac{11\pm \sqrt{361}}{10}=\frac{11\pm 19}{10}= \left [ {{3\ \textgreater \ 1\; ,\; ne\; podxodit} \atop {-0,8}} \right. \\\\sint=-0,8\\\\ t=(-1)^{n}arcsin(-0,8)+\pi n=(-1)^{n+1}arcsin0,8+\pi n,\; n\in Z\\[/latex]