6sin^2x+sin2x=2 очень прошу

[latex]sin2x=2sinx\cdot cosx\\ 6sin^2x+2sinx\cdot cosx=2\\ 6sin^2x+2sinx\cdot cosx-2(sin^2x+cos^2x)=0\\ 4sin^2x+2sinx\cdot cosx-2cos^2x=0\\ \frac{4sin^2x+2sinx\cdot cosx-2cos^2x}{cos^2x}=0\\ 4tg^2x+2tgx-2=0\\ 2tg^2x+tgx-1=0\\ 2tg^2x+tgx-1=0\\ 2tg^2x+2tgx-tgx-1=0\\ 2tgx(1+tgx)-(tgx+1)=0\\ (2tgx-1)(tgx+1)=0\\ tgx_1=0,5\\ tgx_2=-1\\ x_1=arctg0,5+ \pi n\\ x_2=- \frac{ 3\pi }{4} + \pi n[/latex]