6x^2-5x больше =-1/4x^2-1 алгебра

[latex]6x^2-5x \geq - \frac{1}{4}x^2 -1\\6x^2-5x+\frac{1}{4}x^2+1 \geq 0\\6,25x^2-5x+1 \geq 0\\x= \frac{5 \frac{+}{}0 }{6.25*2}= \frac{2}{5}=0.4[/latex]