(√7-2)x*2-4x+(2+√7)=0

[latex] (\sqrt{7}-2)x^2-4x+(2+\sqrt{7})=0\\ (\sqrt{7}-2)x^2-4x+(\sqrt{7}+2)=0\\ D=(-4)^2-4*(\sqrt{7}-2)*(\sqrt{7}+2)=16-4(\sqrt{7}^2-2^2)=\\ =16-4(7-4)=16-4*3=16-12=4\\ \sqrt{D} = \sqrt{4} = 2\\ x1=\frac{4+2}{\sqrt{7}-2} = \frac{6}{\sqrt{7}-2}\\ x2 = \frac{4-2}{\sqrt{7}-2} = \frac{2}{\sqrt{7}-2} [/latex]