(8c^2+10c-3)/(8c^3+36c^2+54c+27)

[latex] \frac{8c^2+10c-3}{8c^3+36c^2+54c+27} = \frac{(2c+3)(4c-1)}{(2c+3)^3} = \frac{4c-1}{(2c+3)^2} = \frac{4c-1}{4c^2+12c+9 \\ } [/latex] -------------------------------------- D=100+4*3*8=196=14² c₁=(-10-14)/16=-3/2 c₂=(-10+14)/16=1/4 8c²+10c-3=8(c+3/2)(c-1/4)=(2c+3)(4c-1)