8x = 12 /(x - 40) Решите

[latex]8x= \frac{12}{x-40}[/latex] [latex]8x= \frac{12}{(x-40)} , x \neq 0[/latex] 8x(x-40)-12=0 [latex]8x^{2} -320x-12=0[/latex] [latex]4(2x^{2} -80x-3)=0[/latex] [latex]2x^{2} -80x-3=0[/latex] [latex]D=(-80)^{2} -4*2*(-3)= \sqrt{6424}[/latex] [latex] x_{1} = \frac{80-2 \sqrt{1606} }{4} = \frac{40- \sqrt{1606} }{2} [/latex] [latex] x_{2} = \frac{80+2 \sqrt{1606} }{4} = \frac{40+ \sqrt{1606} }{2} [/latex]